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Bash regex help

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Top Forums Shell Programming and Scripting Bash regex help
# 1  
Old 10-10-2012
Bash regex help
I've been using the following regex below in a bash script on RHEL 5.5 using version
GNU bash, version 3.2.25(1)-release

I've tried using the script on RHEL 6.3 which uses GNU bash, version 4.1.2(1)-release

I assume there's been alot of changes to bash since that's quite a jump in revisions. I'm wondering if anyone can help me sort what might have to be modified in the code to make this work again.

If I enter an e-mail address in a simple format like:

user.user@test.com the scripts sees this as an invalid e-mail now, whereas before this would pass the regex.


Code:
#!/bin/bash
echo Enter the users e-mail address.

read ADDRESS

if [[ "$ADDRESS" =~ "^[A-Za-z0-9._%+-]+@[A-Za-z0-9.-]+\.[A-Za-z]{2,4}$" ]] ; then
   echo $?
   echo Proceeding!!
else
   echo $?
   echo You entered an invalid e-mail address!!!
exit 1
fi

Moderator's Comments:
Mod Comment Please view this link: How to use code tags
Last edited by Scrutinizer; 10-10-2012 at 04:01 PM.. Reason: Removed extra code tags...
# 2  
Old 10-10-2012
There should not be double quotes around the regex...
This User Gave Thanks to Scrutinizer For This Post:
woodson2
# 3  
Old 10-10-2012
Quote:
Originally Posted by Scrutinizer
There should not be double quotes around the regex...

So simple..Thanks
# 4  
Old 10-10-2012
You also shouldn't depend on the meaning of $?, after the test (if [ ...]).

Code:
$ cat SomeScript
ls sdadadsasdasd
echo $?

ls sdadadsasdasd

if [ 1 -eq 1 ]; then
  echo $?
  echo Yes, 1 is 1
else
  echo $?
  echo No, not 1 is not 1
fi


$ ./SomeScript
ls: sdadadsasdasd: No such file or directory
1
ls: sdadadsasdasd: No such file or directory
0
Yes, 1 is 1

# 5  
Old 10-10-2012
Quote:
Originally Posted by Scott
You also shouldn't depend on the meaning of $?, after the test (if [ ...]).

Code:
$ cat SomeScript
ls sdadadsasdasd
echo $?

ls sdadadsasdasd

if [ 1 -eq 1 ]; then
  echo $?
  echo Yes, 1 is 1
else
  echo $?
  echo No, not 1 is not 1
fi


$ ./SomeScript
ls: sdadadsasdasd: No such file or directory
1
ls: sdadadsasdasd: No such file or directory
0
Yes, 1 is 1

Thanks, however I wasn't relying on the exit status, I just put that in the script temporarily while trying to test.
# 6  
Old 10-10-2012
I know, but just thought it worth mentioning Smilie
# 7  
Old 10-10-2012
I'm having the same issue in this regex. if I remove the quotes in this one then
something like Test Name comes back as invalid whereas in bash 3.2 Test Name would be valid but test name would be invalid. The idea is the first and last name need to start with an upper case letter of course.

Code:
if [[ "$givenName" =~ "^[A-Z]([a-z]|'[A-Za-z])+\s+[A-Z]([a-z]|'[A-Za-z])+(-[A-Z]([a-z]|'[A-Za-z])+)*$" ]]
  then
    echo -e "${bldgrn}$givenName is a valid name.${txtrst}"
else
    echo -e "${bldred}$givenName is an invalid name!!${txtrst}"
exit 1
fi
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