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Sending Sed/Echo output to Variable

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# 1  
Old 08-28-2012
Sending Sed/Echo output to Variable
I have a variable $WORDS that contains a string
Quote:
one two @three !four
Then i want to use sed to break it up.
Code:
echo $WORDS | sed 's/[!-/:-@[-`{-~]/ /g'

I tried setting this as a variable by doing
Code:
WORDS2=`echo $WORDS | sed 's/[!-/:-@[-`{-~]/ /g'`

But when i do this it does not return me to the prompt properly
ie.
Code:
jmpprd-v1>
jmpprd-v1> set WORDS2=`echo $WORDS | sed 's/[!-/:-@[-`{-~]/ /g'`
>
>

Then i have to ctrl+c to exit and it does not set it.
What am i missing here?
# 2  
Old 08-28-2012
Hi
Adding a backslash

Code:
WORDS2=`echo $WORDS | sed 's/[!-/:-@[-\`{-~]/ /g'`

Guru.
Last edited by guruprasadpr; 08-28-2012 at 02:48 AM.. Reason: added text
This User Gave Thanks to guruprasadpr For This Post:
nitrobass24
# 3  
Old 08-28-2012
In the line:
Code:
set WORD2=`echo $WORDS | sed 's/[!-/:-@[-`{-~]/ /g'`

you have an odd number of back-ticks (highlighted in red). Hence, the shell is waiting for another back-tick to complete the command line and displaying the secondary prompt.

Use what guruprasadpr suggested or use:
Code:
typeset WORDS2=$(echo $WORDS | sed 's/[!-/:-@[-`{-~]/ /g')

Also, I think that set should be typeset. Or are you using C shell?
Last edited by elixir_sinari; 09-27-2012 at 08:16 AM..
# 4  
Old 08-28-2012
Alternatively you may use tr too:
Code:
echo $WORDS | tr -d '!-/:-@[-\`{-~'

# 5  
Old 08-28-2012
thanks for all of the suggestions/help
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