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Average values in a column based on range

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# 1  
Old 03-23-2012
Average values in a column based on range
Hi i have data with two columns like below.

I want to find average of column values like if the value in column 2 is between 0-250000 the average of column 1 is some xx and average of column2 is ww then if value is 250001-5000000 average of column 1 is yy and average of column 2 is zz.
And my interval to find the average is 250000

Can anyone help me on this.

Thanks.


Code:
198.25	250000
192	300000
128.5	100000
88	123456
96.25	340000
167.75	540000
401	430000
2008.5	199074
2883	199072
214.75	198959
621.5 198931

Last edited by bhargavpbk88; 03-23-2012 at 05:08 PM..
# 2  
Old 03-23-2012
Show the output you'd want for this input please.
# 3  
Old 03-23-2012
output for my input
This is output to given input


Code:
877.5	181356
229.83	356666.66
167.75	540000

# 4  
Old 03-23-2012
I cannot find any combination of numbers from that first column which, in sum or average, equal 877.5

The average of
Code:
128.5	100000
96.25	340000
401	430000
2883	199072

...comes close, but I can't understand why they'd be averaged together, since they're in different slots according to your criteria
# 5  
Old 03-23-2012
Average is based on 2nd column if 2nd column values are in between 0-250000 average them then if values are in between 250001-500000 average them them if values are in between 500001-750000 average them the interval for each is 250000.
Your answer is almost near but i have huge data file to perform this so i may get error in final output.
Anyways thanks for replying.

---------- Post updated at 05:23 PM ---------- Previous update was at 05:05 PM ----------

sum coming to 877.5 is


Code:
(198.25 + 128.5 + 88 + 2008.5 + 2883 + 214.75 + 621.5)/7 = 877.5

# 6  
Old 03-23-2012
Hi, try this:
Code:
awk '{i=int(($2-1)/r); A[i]+=$1; B[i]+=$2; C[i]++} END{for(i in A)print A[i]/C[i], B[i]/C[i]}' r=250000 infile

This User Gave Thanks to Scrutinizer For This Post:
bhargavpbk88
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