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How to print Specific keyword, by using awk?

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# 1  
Old 03-09-2012
Tools How to print Specific keyword, by using awk?
How to print Specific keyword, by using awk.?

Code:
prime:root:[/usr/home/myserver/$ cat input.log 
1620002_M_20120309033204_78.txt
1620002_M_20120309033232_1457.txt
1620002_M_20120309033240_10000.txt
1620002_M_20120309033241_10000.txt
1620002_M_20120309033242_5985.txt
1620002_M_20120309033243_307.txt
1620002_M_20120309033246_10000.txt
1620002_M_20120309033247_10000.txt
1620002_M_20120309033248_10000.txt
1620002_M_20120309033249_10000.txt
1620002_M_20120309033250_3760.txt
1620002_M_20120309033251_692.txt
1620002_M_20120309033254_6656.txt
1620002_M_20120309033255_157.txt
1620002_M_20120309033302_696.txt
1620002_M_20120309033303_127.txt
1620002_M_20120309033304_7408.txt

I want output.
Code:
78
1457
10000
10000
5985
307
10000
10000
10000
10000
3760
692
6656
157
696
127
7408

I try with command
Code:
cat input.log |awk -F"_" '{print$4}'

Please Guide Line.

Thank
# 2  
Old 03-09-2012
Code:
 awk -F'[_.]' '{print $4}' inputfilename > newfilename

# 3  
Old 03-09-2012
Quote:
Originally Posted by jim mcnamara
Code:
 awk -F'[_.]' '{print $4}' inputfilename > newfilename

I Try but not work.
# 4  
Old 03-09-2012
In what way does it "not work"?

What's your operating system?

Have you tried nawk instead of awk?
# 5  
Old 03-09-2012
Why awk?
Code:
while IFS='.' read a b; do echo ${a##*_}; done < input.log

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