Shell Programming and Scripting

Hi,
I have a snippet like below.
Based on variable i, i wish to print 1,2,3,4,5th columns to Sample files.
For each loop, one column from contetn and results will be pused to sample files. But i have a problem here

Code:

i=1
while [ $i -le 5 ]; do
`awk -F"\t" '{print $($i)}' $content > Sample_${i}_original`;
`awk -F"\t" '{print $($i)}' $results > Sample_${i}_results`;
i=`expr $i+1|bc`;
done

Variable i is not being interpolated inside awk command

Code:

'{print $($i)}'

I tried many variations of it like

Code:

"{print $($i)}"
'{print $i}'

but nothing works.
How can i modify the code to make variable i is interpolated under print of awk command?
Appreciate your responses.

Code:

awk -F"\t" '{print \$$i}'

Didn't worked.
Output from set -x is below. No Interpolation is happening.
I am using korn shell.

Code:

awk -F\t {print $$i}

Right. I missed that you used single quotes. Try this:

Code:

awk -F"\t" "{print \$$i}"

\$$i turning out to take Procees ID. You can see the set -x below

Code:

awk -F\t {print 14306i}

I tried with below variation and it is working now.

Code:

awk -F"\t" "{print $"$i"}"

Thanks for your inputs.