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search for a pattern using grep

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# 1  
Old 01-17-2012
search for a pattern using grep
Hi
I am facing the below problem.

I have set of lines in which i have to search for only the line which matches with the pattren "/" only.

input:-
Code:
/*+ some text */
/*+ some text */
/* Remove rows from a table of survey results. */
/* Add a survey respondent's name and answers. */
/* Remove rows from a table of survey results. */
/* Add a survey respondent's name and answers. */
/*sometext*/
SELECT salary / commission INTO sal_calc FROM employees_temp

output:-
Code:
SELECT salary / commission INTO sal_calc FROM employees_temp

the lines with /*+ or /* should be ignored.

i am using
Code:
egrep -w '\/' filename

but this is resulting me all the above rows.

please help.
Last edited by Franklin52; 01-17-2012 at 08:10 AM.. Reason: Please use code tags for code and data samples, thank you
# 2  
Old 01-17-2012
Based on the input given .. Just give space before and after / in grep pattern ..
Code:
$ grep " / " infile
SELECT salary / commission INTO sal_calc FROM employees_temp

# 3  
Old 01-17-2012
Quote:
Originally Posted by jayan_jay
Based on the input given .. Just give space before and after / in grep pattern ..
Code:
$ grep " / " infile
SELECT salary / commission INTO sal_calc FROM employees_temp

sorry i missed to mention.
the statements may or may not have spaces in between.
so this dosen't work when statements do not have space before or after /
# 4  
Old 01-17-2012
Try this:
Code:
grep -v "^/\*" inputfile

An awk:
Code:
awk '/^\/\*/{next}'1 inputfile

# 5  
Old 01-17-2012
Smilie...
its not working..
it is giving me all the lines in my file and even lines with /*.
# 6  
Old 01-17-2012
Works for me.

Code:
$ cat inputfile
/*+ some text */
/*+ some text */
/* Remove rows from a table of survey results. */
/* Add a survey respondent's name and answers. */
/* Remove rows from a table of survey results. */
/* Add a survey respondent's name and answers. */
/*sometext*/
SELECT salary / commission INTO sal_calc FROM employees_temp
$
$ grep -v "^/\*" inputfile
SELECT salary / commission INTO sal_calc FROM employees_temp
$

Try this perl one-liner:
Code:
perl -ne '(!/^\s*\/\*/)&&print' inputfile

# 7  
Old 01-17-2012
the file has other lines also other than lines having only / like
Code:
/*+ some text */
/*+ some text */
/* Remove rows from a table of survey results. */
/* Add a survey respondent's name and answers. */
/* Remove rows from a table of survey results. */
/* Add a survey respondent's name and answers. */
/*sometext*/
SELECT salary / commission INTO sal_calc FROM employees_temp
some text some text some text
some text some text some text
some text some text some text
some text some text some text

in this sace it is printing the above 4 lines also.
Last edited by Franklin52; 01-17-2012 at 08:09 AM.. Reason: Please use code tags for code and data samples, thank you
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