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Empty out multiple files with a single command?

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# 1  
Old 01-16-2012
Empty out multiple files with a single command?
I have a log directory:
/logs/foo.log
/logs/bar.log
/logs/err.out

I'm trying to find a way to

> /logs/*.log
> /logs/*.out

to blank them out, but of course, that doesn't work.

Any suggestions?
# 2  
Old 01-16-2012
Try this:

Code:
find /logs \( -name "*.log" -o -name "*.out" \) -type f | while read f; do >$f; done

Easy huh?? Smilie
# 3  
Old 01-16-2012
Ah, so that's all I was missing... the whole thing.

Thanks so much, xor
# 4  
Old 01-16-2012
Alternatively:
Code:
 for i in /logs/*.log /logs/*.out; do [[ -f $i ]] && > $i; done

# 5  
Old 01-16-2012
Alternatively, if there is only one directory:
Code:
for i in /logs/*.log /logs/*.out; do 
  :>"$i"
done

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