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# 1  
Old 03-11-2005
unix cmd
Hi
i want a shell script to get the date which is mentioned in the first line of a file.

file format is:
#EOD rates on 20050228 at 22:06:37
--------
--------
-------

first line length is always fixed.
# 2  
Old 03-11-2005
head -1 Your_File | awk -F " " {print $4}
# 3  
Old 03-12-2005
You can also use

Quote:
head -1 yourfile | cut -d" " -f 4
# 4  
Old 03-13-2005
awk 'NR==1{print $4;exit}' file1
# 5  
Old 03-14-2005
Quote:
Originally Posted by sasi
Hi
i want a shell script to get the date which is mentioned in the first line of a file.

file format is:
#EOD rates on 20050228 at 22:06:37
--------
--------
-------

first line length is always fixed.
You can use sed as,

sed '1!d;s/^.*\(........\)$/\1/' <filename>

so that it will print
22:06:37

HTH.
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