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find a word and print n lines before and after the match

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# 1  
Old 12-09-2011
find a word and print n lines before and after the match
how to find a word and print n lines before and after the match until a blank line is encounterd
# 2  
Old 12-09-2011
Homework ?? What is your try ..
# 3  
Old 12-09-2011
i googled and got some info..but cant put all together to make it work.. grep -n will give the line number of the word i am searching for .. and i took that line number in awk '{$value+1}' but this didnt work..

then saw getline utility in awk but it prints only one line..
# 4  
Old 12-09-2011
If not GNU grep ..

Before 5 lines ..
Code:
sed -n '/pattern/q;p' infile | tail -5

After 5 lines ..
Code:
nawk 'c-->0;/pattern/{print;c=5}' infile

Last edited by jayan_jay; 12-09-2011 at 03:44 AM..
# 5  
Old 12-09-2011
Quote:
Originally Posted by chidori
how to find a word and print n lines before and after the match until a blank line is encounterd
Which OS?

try grep -A and grep -B if those are available for you.
# 6  
Old 12-09-2011
solaris 10

grep -A and -B are for gnu tool right?

what i exactly want is..
Code:
G
M

A
B
C
D

E
F

Assume the above is the file content. i want to find for the letter 'B' and print lines above
and below it until a blank line is encountered.

so my result should be
Code:
A
B
C
D

# 7  
Old 12-09-2011
on solaris, grep -A and grep -B should work.

try
Code:
/usr/xpg4/bin/grep
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