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loop help

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# 1  
Old 12-02-2011
loop help
Ok i have this code below when i enter option 3, once it goes through and that part is done, i cant get it to display the menu options again. It only works with "break ;;" but the break just exits the script
Code:
while true do 
clear 
echo 
"Menu Options: " 
echo "1. Create Script" 
echo "2. Show Script" 
echo "3. Exit" 
echo " Choose: " read options        
case "${options}" in            

1)     
read -p "Enter script name" $name         
echo "$name" >> web.txt          
;;         

2)     
echo "Your script"         
cat web.txt        
;; 

3)     
read -p "Publish your public_html directory? (y|n)" publish

if [ "$publish" = "y" ];
then
read -p "Enter name of webpage to publish:" publishedpage1
cp WEB.txt ~/public_html/$publishedpage1
echo "Enter to continue"
else
echo "Webpage has not been published"
fi
;; 

4)    
echo "Exitting."        
exit 0                    
 ;;  
esac done

# 2  
Old 12-02-2011
Quote:
Originally Posted by gangsta
Ok i have this code below when i enter option 3, once it goes through and that part is done, i cant get it to display the menu options again. It only works with "break ;;" but the break just exits the script
If the code is really as you've posted it, it must be throwing syntax errors all over the place, not just not working right. You've got line breaks -- and lack of line breaks -- in very strange places. You have to have them in the right places in a shell script.

Code:
while true
do 
        clear 

        echo "Menu Options: " 
        echo "1. Create Script" 
        echo "2. Show Script" 
        echo "3. Exit" 
        echo " Choose: "
        read options

        case "${options}" in
        1)     
                read -p "Enter script name" $name         
                echo "$name" >> web.txt          
                ;;         

        2)     
                echo "Your script"         
                cat web.txt        
                ;; 

        3)
                read -p "Publish your public_html directory? (y|n)" publish

                if [ "$publish" = "y" ];
                then
                        read -p "Enter name of webpage to publish:" publishedpage1
                        cp WEB.txt ~/public_html/$publishedpage1
                        echo "Enter to continue"
                else
                        echo "Webpage has not been published"
                fi
                ;; 

        4)    
                echo "Exitting."        
                exit 0                    
                 ;;  
        esac
done

Does it work now that I've fixed your linebreaks?
# 3  
Old 12-02-2011
sorry about that, i was trying to fix up the spacing and everything. But the script works, but i cant solve my problem of displaying the menu options again after executing option 3
# 4  
Old 12-02-2011
It works fine on this end. You never see what any of your options print because it immediately clears the screen and reprints the menu, but it works.

I've noticed that your menu doesn't match your case statement. Make sure you're doing what you think you're doing.

Other than that, I'm puzzled... It seems to do what you want. What's your system, what's your shell?
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