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matching a regex using egrep not working

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# 1  
Old 11-28-2011
matching a regex using egrep not working
Hi,

I'm trying to validate if a string matches a regular expression, but it is not working. Am I missing something? Do I need to scape any of the characters?

Code:
 if echo 'en-GB' | egrep '([a-zA-Z]{1,8})(-[a-zA-Z0-9]{1,8})*' >/dev/null; then
  echo Valid value
 fi


Thanks in advance
# 2  
Old 11-28-2011
Your regexp works with GNU grep, but you might need to escape the interval expressions (\{1,8\}) in some versions.
# 3  
Old 11-28-2011
Thanks CarloM.

I tried this:

Code:
if echo 'en-GB' | egrep '([a-zA-Z]\{1,8\})(-[a-zA-Z0-9]\{1,8\})*' >/dev/null; then
echo Valid value
fi

but still didn't work. Is anything else that might be wrong?
Last edited by skrtxao; 11-28-2011 at 11:56 AM..
# 4  
Old 11-28-2011
Your first post works for me...
Code:
root@bt:~#  if echo 'en-GB' | egrep '([a-zA-Z]{1,8})(-[a-zA-Z0-9]{1,8})*' >/dev/null; then
>   echo Valid value
>  fi
Valid value

which is your OS?

--ahamed
# 5  
Old 11-28-2011
Hi ahamed,

I believe is SunOS 5.10...
# 6  
Old 11-28-2011
Use /usr/xpg4/bin/egrep - Solaris egrep doesn't support interval expressions at all.
This User Gave Thanks to CarloM For This Post:
skrtxao
# 7  
Old 11-28-2011
That seems to work!

Thanks for the help.

skrtxao.
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