Shell Programming and Scripting

I do not have ggrep

regexp=something
sed -n /$regexp'/{N;p;}'

perderabo seems to get it all..This should work..

Close. VERY close. I am almost there.

Now, Perderabo, let's say I have several "somethings"...kinda like this:

regexp=something
regexp2=anothersomething
regexp3=lastsomething

How would I use the sed -n /$regexp'/{N;p;}' in that case????


-cd

I have no idea what that's supposed to mean...but maybe...

Code:

for regexp in something anothersomething lastsomething ; do
        sed -n /$regexp'/{N;p;}'  <  datafile
done

Try this:

#!/bin/ksh
while read regexp;do
sed -n /$regexp'/{N;p;}
done


name this file regexp.ksh and execute this as

. regexp.ksh < regexp.txt

where regexp.txt has all those
something
anothersomething
lastsomething

I was afraid my explanation would be vague. Lemme try to be more specific.

Suppose the following three alarms are in a log file:

Wed Feb 2 07:02:22 <vsm> 91041 Line 37 Severity 4 Vps 8
No Host Found - TN:2135572346

Wed Feb 2 07:02:22 <vsm> 91041 Line 23 Severity 4 Vps 3
No Host Found - TN:2156772216

Wed Feb 2 07:02:22 <vsm> 91041 Line 12 Severity 4 Vps 1
No Host Found - TN:2165523456

Now...let's suppose that the only one I really care about is the one in blue. What I want to do is prompt a user to tell me the "Line" number, then the "Vps" number. So for this example, the user would input Line 23 and Vps 3.

The script would then look at all 91041 alarms, find the one(s) for Line 23 and Vps 3, then report them back to me. As a bonus, it would also report the second line of the 91041 alarm to me, which is important because it has the TN. In other words, after running my script, one would see:

Wed Feb 2 07:02:22 <vsm> 91041 Line 23 Severity 4 Vps 3
No Host Found - TN:2156772216

Does that make more sense???

-cd