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Passing value as a command line argument in awk script.

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# 1  
Old 07-25-2011
Passing value as a command line argument in awk script.
I have one working awk command line. Which taking data from the “J1202523.TXT” file and generating the “brazil.dat” file. PFB code.
Code:
awk '{ DUNS = substr($0,0,9);if ( substr($0,14,3) == "089" ) print DUNS }' J1202523.TXT > Brazil.dat

But now I want to pass two parameter as a command line argument .
1. 089
2. brazil
Please help me how can I pass command line parameter in awk script.
Last edited by radoulov; 07-25-2011 at 06:32 AM.. Reason: Code tags.
# 2  
Old 07-25-2011
You can pass it with -v
Code:
awk -v outfln="brazil.dat" -v somevar="089" '{ DUNS = substr($0,0,9);if ( substr($0,14,3) == somevar ) print DUNS > outfln  }' J1202523.TXT

This User Gave Thanks to Peasant For This Post:
humaemo
# 3  
Old 07-25-2011
i just little modify the script.

Code:
awk -v outfln="$2" -v somevar="$1" '{ DUNS = substr($0,0,9);if ( substr($0,14,3) == somevar ) print DUNS > outfln  }' J389247.TXT


it is working fine. thanks for your help. Smilie
Last edited by radoulov; 07-25-2011 at 06:33 AM.. Reason: Code tags!
# 4  
Old 07-25-2011
Code:
#!/bin/sh
awk -v var1="$1"  '{ ... }' >"$2".dat

Don't forget chmod +x this file.
# 5  
Old 07-25-2011
sure Smilie
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