grep regex, match exact string which includes "/" anywhere on line.


 
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# 1  
Old 06-30-2011
grep regex, match exact string which includes "/" anywhere on line.

I have a file that contains the 2 following lines (from /proc/mounts)

/dev/sdc1 /mnt/backup2 xfs rw,relatime,attr2,noquota 0 0
/dev/sdb1 /mnt/backup xfs rw,relatime,attr2,noquota 0 0

I need to match the string in the second column exactly so that only one result is returned, e.g.

Code:
> grep "/mnt/backup" /proc/mounts
/dev/sdc1 /mnt/backup2 xfs rw,relatime,attr2,noquota 0 0
/dev/sdb1 /mnt/backup xfs rw,relatime,attr2,noquota 0 0
>

This is no good as it returns both lines.

Code:
> grep  "\<backup\>" /proc/mounts
/dev/sdb1 /mnt/backup xfs rw,relatime,attr2,noquota 0 0
>

Works better as it only matches the exact string "backup" (excluding backup2). But I want to match only the entire string "/mnt/backup", but it appears the forward slashes affect the regex and I cannot figure out how to get them interpreted correctly. I have tried escaping them using \ but this does not work.

Code:
> grep  "\</mnt/backup\>" /proc/mounts
>
> grep  "\<\/mnt\/backup\>" /proc/mounts
>

I have tried all sorts of other options which would just create noise in the thread and therefore are ommited...

Thanks
# 2  
Old 06-30-2011
Code:
grep -w "/mnt/backup" /proc/mounts

This User Gave Thanks to itkamaraj For This Post:
# 3  
Old 06-30-2011
Smilie, haha so simple. I did read the man page but obviously not thoroughly enough.

Thanks for that.
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