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Regular expression inside case statement notworking

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# 1  
Old 06-17-2011
Regular expression inside case statement notworking
I have the following script:
Quote:
tail -f /var/log/mymessages |
while read line
do
case $line in
"ERROR*memory") printf "%s\n" "$line" |
mailx -s "OpenSIPS Memory Error" pnc@domain.com
;;
esac
done
For catching errors like:
Quote:
ERROR:nathelper:nh_timer: out of pkg memory
ERROR:registrar:build_contact: no pkg memory left
ERROR:core:build_res_buf_from_sip_req: out of pkg memory ; needs 45926
But the regular expression ERROR*memory inside case doesn't seem to be working.
The output of bash -x scriptname is:
Quote:
+ tail -f /var/log/mymessages
+ read line
+ case $line in
+ read line
+ case $line in
+ read line
+ case $line in
+ read line
+ case $line in
+ read line
+ case $line in
+ read line
Please help
# 2  
Old 06-17-2011
Remove the quotes:

Code:
ERROR*memory

This User Gave Thanks to radoulov For This Post:
proactiveaditya
# 3  
Old 06-17-2011
Thanks,works like a charm.
I need another help, now the script is unable to catch any new line matching the pattern
Quote:
ERROR*memory
Is there any fundamental error in the script?
# 4  
Old 06-17-2011
The output that passes through the pipe is buffered, I suppose you just need to wait until the buffer gets flushed ...
(just add some more lines and you should see the script working).
This User Gave Thanks to radoulov For This Post:
proactiveaditya
# 5  
Old 06-17-2011
Does ERROR.*memory and ERROR*memory mean the same?
# 6  
Old 06-17-2011
No, you're using shell pattern matching, not regular expressions. The dot ( . ) has no special meaning in shell pattern matching
(it just matches a literal dot).
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