Login or Register to Ask a Question and Join Our Community


Shell Programming and Scripting

Command param subst to reg expression

Login to Discuss or Reply to this Discussion in Our Community

 
Thread Tools Search this Thread
Top Forums Shell Programming and Scripting Command param subst to reg expression
# 1  
Old 12-21-2004
Question Command param subst to reg expression
I want to find out Row which starts with, the user specified details to a script.
In general I know what command to be given.
awk '$0~/^Vi/' BReject

But I need to pass on $1 param of command line at the place of 'Vi'.
I tried with -v subst=$1
awk -v subst=$1 '$0~/^subst/' BReject
But it couldnt work.

Any suggestions, Solution must be restricted to awk.
# 2  
Old 12-21-2004
12345
Last edited by druuna; 05-21-2009 at 10:11 AM..
druuna
# 3  
Old 12-21-2004
Quote:
Originally posted by druuna
I wouldn't know a way of putting a variable into a /^VAR/ construct.
You would if you would read our faqs or at least the one entitled "Passing variables/arguments/parameters to commands".
# 4  
Old 12-21-2004
Data
Druuna

It doesnt work. Requirement is it should start with the given pattern.
Actually I have a fixed width file. So there is no fields within.
Its true I need suitable replacement for var within, /^var/.
# 5  
Old 12-21-2004
It worked with me for , at the place of var, '$1'.

Thanks.
# 6  
Old 12-21-2004
i try some thing like this ......



awk -v subst="bhargav" '{ if(match($0,subst) == 1 ){ print $0 } }' txt.tmp
Login or Register to Ask a Question

Previous Thread | Next Thread

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

REG Expression

Need your help in creating regular expression for particular set. let say I have given two dates 20130623 to 20140625. I need to create regular for the dates which fall in between above two dates. (4 Replies)
Discussion started by: gvkumar25
4 Replies

2. Shell Programming and Scripting

Confusion with Reg expression

I want to make a REG Expression to validate the directory. my dirsample is below: /abc/abc/abc abc/abc/abc abc/abc/abc/ /abc/a bc/abc /a bc/abc/abc /abc/abc/a bc / abc/abc/abc /abc/ abc/abc /abc/.abc /.abc/abc / // /abc /.abc And my code is below: grep -E '^\/(+\/?)+$' dirsample (4 Replies)
Discussion started by: franksunnn
4 Replies

3. Shell Programming and Scripting

reg expression in perl

how to uniquely match each of the words seperated by / in perl ${REP_PATH}/FUNCTIONAL/wide1c_1.0V/max/qor.rpt https://www.unix.com/images/misc/progress.gif (5 Replies)
Discussion started by: dll_fpga
5 Replies

4. Shell Programming and Scripting

reg expression in perl

./GEN_SCR.pl -f ${REP_PATH}/FUNCTIONAL/wide1c_1.0V/max/qor.rpt -o ${REP_PATH}/FUNCTIONAL/GEN2_wide1c_1.0V_max.csv where GEN_SCR.pl is as below...i need to check whether max or min is coming in the argument to the script ...how to do this? ${REP_PATH}/FUNCTIONAL/wide1c_1.0V/max/qor.rpt ... (0 Replies)
Discussion started by: dll_fpga
0 Replies

5. Shell Programming and Scripting

Reg expression

Please let me understand this reg expression (\s+')(.*)('\s+)(.)(.*)(\/.*)/) i have doubt in the below 2.I'm not understanding why back-tick used? (\s+') and ('\s+) (2 Replies)
Discussion started by: dll_fpga
2 Replies

6. Shell Programming and Scripting

awk reg expression

Hello, I have thousand of messages (HL7), I want to use awk to extract only the ones that have a particular value in pv1.18 Each record in the file is the whole HL7 message, ie. when I print $0 I get the whole message MSH EVN PID etc. ,there is an x0d between the segments. I would like to use a... (3 Replies)
Discussion started by: gio001
3 Replies

7. Shell Programming and Scripting

Reg expression For

HI system.sysUpTime.0 : Timeticks: (1519411311) 175 days, 20:35:13.11 From the above output i need only 175days in a perl script.. Please Help (2 Replies)
Discussion started by: Harikrishna
2 Replies

8. Shell Programming and Scripting

perl reg expression

I have regular expression like this ( replace + with \+) ($mod_server) = ($server =~ /\+/\\+/g); the above is failing with error . what's wrong with it . Thanks (1 Reply)
Discussion started by: talashil
1 Replies

9. Shell Programming and Scripting

assign subst|grep|sed command result to a variable

Hi, I'm quite new to scripting and I want to modify following line of an existing script: MYVAR=`subst |grep 'L:\\\:' | sed -e 's/.*\\\//'`; What I have to do is to use the content of a variable instead of the constant expression 'L:\\\:' as the grep string to be matched. Assuming I already... (5 Replies)
Discussion started by: snowbiker99
5 Replies

10. UNIX for Dummies Questions & Answers

Help with Reg. Expression

I need help with this: Can any one tell me what does these below mean: 1. "\(.\).*") != '/' 2. sed 's+^\./++;s+/.*++' 3. sed "s+${f}/+ + Thanks in advance (7 Replies)
Discussion started by: moe2266
7 Replies
Login or Register to Ask a Question