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Old Unix and Linux 03-14-2011
alvin0618 alvin0618 is offline
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Code:
date +%Y%m%d%H

output :
2011031415

I want to get previous hour like this 2011031414. Any one can help ?
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Old Unix and Linux 03-14-2011
pravin27 pravin27 is offline Forum Advisor  
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If you GNU date then use

Code:
date -d'1 hour ago' '+%Y%m%d%H'

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Old Unix and Linux 03-14-2011
alvin0618 alvin0618 is offline
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Quote:
Originally Posted by pravin27 View Post
If you GNU date then use
I am using SunOS LSMS 5.10 .
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Old Unix and Linux 03-14-2011
pravin27 pravin27 is offline Forum Advisor  
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How about this?

Code:
perl -e '@dttime=(localtime(time - 60*60))[2,3,4,5];printf "%4d%02d%02d%02d\n",$dttime[3]+1900,$dttime[2]+1,$dttime[1],$dttime[0];'

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Old Unix and Linux 03-14-2011
alvin0618 alvin0618 is offline
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Quote:
Originally Posted by pravin27 View Post
How about this?

Code:
perl -e '@dttime=(localtime(time - 60*60))[2,3,4,5];printf "%4d%02d%02d%02d\n",$dttime[3]+1900,$dttime[2]+1,$dttime[1],$dttime[0];'

how you show me how to store this result into a variable $target_date ?
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Old Unix and Linux 03-14-2011
pravin27 pravin27 is offline Forum Advisor  
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Code:
##target_date=$(perl -e '@dttime=(localtime(time - 60*60))[2,3,4,5];printf "%4d%02d%02d%02d\n",$dttime[3]+1900,$dttime[2]+1,$dttime[1],$dttime[0];')
##echo $target_date
2011020219

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Old Unix and Linux 03-14-2011
alvin0618 alvin0618 is offline
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Thank you. pravin27
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