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Problem with the shell script for understanding

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# 1  
Old 02-21-2011
Problem with the shell script for understanding
Can Anybody please tell me the meaning of the script:

Code:
#!/bin/sh
str=$@
echo $str | sed 's/.*\\//'
exit 0

# 2  
Old 02-21-2011
Hi,

It is removing all characters until last '\' (included) of your input to the script.

Regards,
Birei
This User Gave Thanks to birei For This Post:
nixhead
# 3  
Old 02-21-2011
Can you explain using individual components
thanks Smilie
# 4  
Old 02-21-2011
Hi,

I don't understand what do you mean.

First line assigns parameters to a variable and the sed command substitutes all characters found until last '\' with nothing (deletes it). In case of none '\' found, doesn't make any modification to the string.

Regards,
Birei
Last edited by birei; 02-22-2011 at 09:50 AM..
This User Gave Thanks to birei For This Post:
nixhead
# 5  
Old 02-21-2011
Now I have understood your meaning Smilie
# 6  
Old 03-18-2011
Quote:
Originally Posted by birei
Hi,

I don't understand what do you mean.

First line assigns parameters to a variable and the sed command substitutes all characters found until last '\' with nothing (deletes it). In case of none '\' found, doesn't make any modification to the string.

Regards,
Birei
Hi you solved my query a long time back but I have a problem here the given script is doing action like this on a sample like:
/var/opt/ericsson/resolution/HPSC/xml/outputxml/Citrix_(3).jpg
to
Citrix_(3).jpg
which shouldn't be its execution.
# 7  
Old 03-18-2011
This is because - i guess - you did a typo error :

instead of
Code:
echo $str | sed 's/.*\\//'

i guess in your script you have
Code:
echo $str | sed 's/.*\///'

by the way instead of
Code:
echo $str | sed 's/.*\///'

you'd better have something like
Code:
echo ${str##*/}

or even directly
Code:
echo ${@##*/}

---------- Post updated at 11:45 AM ---------- Previous update was at 11:35 AM ----------

... oooops i correct what i stated above : the ${@##*/} substitution didn't work ...(ksh)
you should keep with the str intermediate variable

Code:
# echo /whaterver/tree/or/path/here/sand
/whaterver/tree/or/path/here/sand
# set -- $(echo /whaterver/tree/or/path/here/sand)
# echo $@
/whaterver/tree/or/path/here/sand
# echo ${@##*/}
ksh: : bad substitution
# str=$@
# echo ${str##*/}
sand
#

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