AWK Print Line If Specific Character Is Matched


 
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# 1  
Old 01-26-2011
AWK Print Line If Specific Character Is Matched

Hello,

I have a file as such:
Code:

FFFFFFF6C000000     225280     225240          -          - rwxs-    [ shmid=0x7000181 ]
FFFFFFFF79C00000       3240       3240          -          - rwxs-    [ shmid=0x7000181 ]
FFFFFFFF7A000000       4096       4096          -          - rwxs-    [ shmid=0x7000186 ]
FFFFFFFF7A400000         64         64          -          - rwxs-    [ shmid=0x7000186 ]
FFFFFFFF7A700000        288        248          -          - r-x--  libresolv.so.2
FFFFFFFF7A848000         24         24          -          - rwx--  libresolv.so.2
FFFFFFFF7A84E000          8          8          -          - rwx--  libresolv.so.2
FFFFFFFF7A900000         16         16          -          - r-x--  nss_dns.so.1

How do I get awk to only print lines which have the 's' character in position 65. (field 6)

Thanks,

PW

Last edited by Franklin52; 01-26-2011 at 02:31 PM.. Reason: Please use code tags
# 2  
Old 01-26-2011
Code:
awk '$6 ~ "s"' file

# 3  
Old 01-26-2011
Thanks Franklin52, that didn't work, but it did get me in the right direction. I'm using:

Code:
awk '$6 ~ /...s./' file

which seems to do what I need.

Thanks.

PW
# 4  
Old 01-27-2011
Try

awk '{if (substr($0,65,1)=="s")print $0}' filename
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