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using awk to print some columns of a file

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# 1  
Old 12-16-2010
using awk to print some columns of a file
Hi,
i have a file with content
Code:
00:01:20.613 'integer32' 459254
00:01:34.158 459556
00:01:36.626 'integer32' 459255

and i want to print only output as below
Code:
00:01:20.613 459254
00:01:34.158 459556
00:01:36.626 459255

i dont want the word 'integer32' which is the second column.

i tried
Code:
awk -F" " '$2=='integer32' && $3>0 { print $1,$3 }'  zddd.txt >> zresult.txt

but it does not work.
Please assist
Last edited by Scott; 12-16-2010 at 11:56 AM.. Reason: Please use code tags
# 2  
Old 12-16-2010
For the provided input, try this:
Code:
awk '{print $1,$NF}' file

# 3  
Old 12-16-2010
thank you, both worked
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