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listing Directory chronologically based on part of file name

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# 1  
Old 11-10-2010
listing Directory chronologically based on part of file name
hi Everbody,

I had file names as shown
Code:
file_01_20101104.txt
file_01_20101105.txt
file_02_20101104.txt
file_01_20101205.txt
file_03_20101104.txt
file_02_20101105.txt

Now i want to list them based on the date in the file name as shown...
Code:
file_01_20101104.txt
file_02_20101104.txt
file_03_20101104.txt
file_01_20101105.txt
file_02_20101105.txt
file_01_20101205.txt

i cant do it by using the regular ls -ltr as it was sort in the chronologically based on the file creation time ....
can we do it using a single line UNIX command as i have to pass this command to another java program call...

Help is greatly appreciated....

Thanks in advance..

Reddy
Last edited by Scott; 11-10-2010 at 02:00 PM.. Reason: Code tags
# 2  
Old 11-10-2010
Try:
Code:
ls | sort -nt_ -k3,3 -k2,2

This User Gave Thanks to Scrutinizer For This Post:
Reddy482
# 3  
Old 11-10-2010
Thats Awesome...
Perfectly working..

Now can you please explain me the command issued using sort.....
# 4  
Old 11-10-2010
-nsort numerically
-t_ use _ as field separator
-k3,3first use field 3
-k2,2and then use field 2
Last edited by Scrutinizer; 11-10-2010 at 03:10 PM..
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