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Multiple variable substitutions

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# 1  
Old 10-20-2010
Multiple variable substitutions
Is there anyway to accomplish this?
(ksh)

Code:
FILES_TO_PROCESS='NAME1 NAME2'

SOURCE_NAME1=/tmp/myfile
TARGET_NAME1=/somewhere/else
# other file names

for i in $FILES_TO_PROCESS
do
file1=SOURCE_$i
file2=TARGET_$i
echo cp ${$file1} ${$file2}  <-- how do get this to work.
done

# 2  
Old 10-20-2010
Is it what you are trying to achieve ?

Code:
SRC=/tmp/src
DEST=/tmp/dest
for i in file1 file2
do
echo "cp $SRC/$i $DEST/$i"
done

or
Code:
... 
eval file1=\$SOURCE_$i
eval file2=\$TARGET_$i
...
eval echo "cp $file1 $file2"

eval will force the expansion of $var but not the one which is \ protected
so the finale commande after eval should look like
echo "cp $SOURCE_NAME1 $TARGET_NAME1"

Note that this would suppose that you have already setup the 2 other variables
Code:
SOURCE_NAME2=/whateverdir/whaterfile
TARGET_NAME2=/whatevernewdir/whatevernewfile

... which does not currently appear in your code

You could just copy dir
Code:
cp -p /sourcedir/* /targetdir

If you want to move them and rename them at the same time, please give us some clue about how you want them to be renamed
Last edited by ctsgnb; 10-20-2010 at 02:38 PM..
# 3  
Old 10-20-2010
Note the trailing slash to ensure it is a dir.

Code:
(
cd /tmp/src
cp NAME1 NAME2 /tmp/dest/
)

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