Using sed or awk?


 
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# 1  
Old 10-06-2010
Using sed or awk?

What if I wanted to add a word such as IT after the first character and if theres 3 characters, after the 2nd character?

output would be:

G, it H
G, H it P
G, H, P it L

I'm thinking that AWK would be the easiest way to do this... Currently looking it up.

Right now I'm using awk but I can only replace every "," with "it". I dont know how to replace the last "," with the word "it"

My output looks like this :

G it H it
G it H it P it
G it H it P it L it

I just figured out how to target my "," but I dont know how to add in "it"

Last edited by puttster; 10-06-2010 at 09:09 PM..
# 2  
Old 10-06-2010
What is you input?
# 3  
Old 10-06-2010
I'd do it this way:

Code:
awk '{ sub( ",$", " it", $(NF-1) ); print}'


Adds "it" before the last token on the line.

Last edited by agama; 10-06-2010 at 09:20 PM.. Reason: Didn't realise the last comma was being ditched; works now
# 4  
Old 10-06-2010
Quote:
Originally Posted by Scrutinizer
What is you input?
my input is "H","T","Y","P","L" ( increases based off input of user )
Im trying to add a word here "H","T","Y","P"HERE"L"

---------- Post updated at 08:30 PM ---------- Previous update was at 08:25 PM ----------

Quote:
Originally Posted by agama
I'd do it this way:

Code:
awk '{ sub( ",$", " it", $(NF-1) ); print}'


Adds "it" before the last token on the line.
Using your code, I cant get it to be withing the 2nd to last quotes.
However I am really close!

Last edited by puttster; 10-06-2010 at 09:39 PM..
# 5  
Old 10-06-2010
Quote:
Originally Posted by puttster
Using your code, I cant get it to be withing the 2nd to last quotes.
However I am really close!
Yes, my solution was based on different input. Try this:

Code:
awk  -F "," -v OFS="," '{ x = $(NF-1) " it " $NF; NF -=2; ; print $0, x }'

Creates a new 'token' with the last and next to last tokens placing 'it' in between. Shortens the original input line by two tokens, then prints the short string with the synthetic value in x.
# 6  
Old 10-06-2010
Code:
sed 's/,\([^,]*\)$/HERE\1/'

# 7  
Old 10-06-2010
sed might be slightly simpler for this one:

Code:
$ echo '"H","T","Y","P","L"' | sed 's/,\([^,]*\)$/ it \1/'
"H","T","Y","P" it "L"
$

Edit: LOL Scrutinizer, great minds work alike
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