Shell Programming and Scripting

By saying /bin/bash -l , I think you meant --login option, because I am not sure there is a -l option for /bin/bash.

Code:

User Commands                                             BASH(1)
--login
          Make bash act as if it had  been  invoked  as  a  login
          shell (see INVOCATION below).

And --login option, as mentioned above by anarchie, causes recursion, so it keeps printing login message, but never does actually login.

thanks anyways for all your suggestions, I did as norsk hedensk suggested and so far it works fine except, it runs at least 2 processes all the time when I am logged in : the ksh and the bash :

Code:

UID  PID    PPID   C    STIME       TTY     TIME    CMD
me  18264  18258   0   20:04:57     pts/1    0:00   -ksh
me  18286  18264   0   20:05:02     pts/1    0:00   /bin/bash
me  18687  18286   0   20:14:01     pts/1    0:00   ps -af

peace...

That's b/c you didn't really change your shell (because your local sysadmin wouldn't let you). So you're really running a virtual bash inside ksh (someone will correct me if that's not the correct nomenclature). You'll also have to hit CTRL-D twice to exit, or type "exit" two times to truly exit. A minor inconvenience.

your could stop infinite recursion by testing the $SHELL variable. IOnly invofe the bash shell if you are currently NOT in the bash shell.

long option, short option. same thing. use whatever you have.