Cut the last 15 characters off


 
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# 1  
Old 08-31-2010
Cut the last 15 characters off

Hi Gurus,

I am trying to execute the below command. However the output shows the value + path of the folder where the command is being executed. But I am only interested in the value but not the path.

Code:
du -hs /aps/inf/SeLogs

when I execute the above command, output is

Code:
32G /aps/inf/SeLogs

Is there a way to cut only the 'path' portion of it.

Thanks in advance
Sam
# 2  
Old 08-31-2010
Code:
du -hs /aps/inf/SeLogs | cut -f1

# 3  
Old 08-31-2010
Code:
du -hs /aps/inf/SeLogs | awk '{print $2}'

tyler_durden
# 4  
Old 08-31-2010
Using Parameter Substitution

If the code never contains whitespace

Code:
a=$(du -hs /aps/inf/SeLogs); echo ${a#*' '}

If the code does contain whitespace you need to use

Code:
a=$(du -hs /aps/inf/SeLogs); echo ${a##*' '}

but the path cannot contain any whitespace.

Mike

Last edited by Michael Stora; 08-31-2010 at 04:52 PM..
# 5  
Old 08-31-2010
Hey Gurus,

They all work. Thanks for quick turnaround.

-Sam
# 6  
Old 09-01-2010
Quote:
Originally Posted by durden_tyler
Code:
du -hs /aps/inf/SeLogs | awk '{print $2}'

tyler_durden
if only value is required ( as per the question ) it has to be $1.
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