Shell Programming and Scripting

i have a variable MYHOST that has my host name.depending on the host i have an array like A_<hostname>.Everytime i need to append the hostname to A_ to get the array.but in the shell script i am nt able to access the members of that array.

code of what i hav done:

export temp=A_$MYHOST
for d in $((temp))
do
...
...
...
done

now i get an arithmetic syntax error in the statement :"for d in $((temp))"

thanks in advance

Code:

for d in $temp
do
    # your code here
done

Try that

If variable temp contains the name of your array, I think you want to expand it like this:

Code:

for d in "${!temp[@]}"

Each element of the array named by temp will be quoted.

The code as written by the OP creates a "normal" environment variable, so simply writing $temp allows the for loop to work with each word.

@jim

im not able to refer still getting the same error...



@....
for d in "${!temp[@]}"

still gets only a value 0 only and not the array values....

A_<hostname>=(1 2 3)
temp has A_<hostname> as its value....i now want to get the values from A_<hostname> array....

can you tell us the output of below comands.

Code:

echo $MYHOST
echo $A_MYHOST

$MYHOST
tragedy

$A_MYHOST

no value is displayed