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awk gsub with variables?

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# 1  
Old 06-30-2010
awk gsub with variables?
Hey,

I would like to replace a string by a new one. Teh problem is that both strings should be variables to be flexible, because I am having a lot of files (with the same structure, but in different folders)
Code:
for i in daysim_*
do
    cd $i/5/
    folder=`pwd |awk '{print $1}'`
    awk '{ if (NR==14) {gsub($2, $folder); print} }' ill_5_06.hea
    cd ../..
done

But of course it doesn't work. So the problem is how to deal with the variable $folder in gsub?

Thanks for any suggestions, Sam.
# 2  
Old 06-30-2010
IMO double post of:

https://www.unix.com/shell-programmin...line-line.html

Thread closed.
# 3  
Old 06-30-2010
Code:
awk '{ if (NR==14) {gsub($2, f); print} }' f="${folder}" ill_5_06.hea

BTW, I think your 'gsub()' is either incomplete and/or incorrect:
Code:
     gsub(ere,repl[,in])
           Behave like sub  (see  below),  except  that  it  will
           replace  all  occurrences  of  the  regular expression
           (like the ed utility global substitute) in  $0  or  in
           the in argument, when specified.

Moderator's Comments:
Mod Comment vgersh99,

His problem is solved, check the thread mentioned above.

Franklin

EDIT: Thread reopend by request of ergy1983
Last edited by Franklin52; 06-30-2010 at 05:39 PM..
# 4  
Old 07-01-2010
Hmm, yeah, but it doesn't work.

it works, if I am using the gsub like this:
Quote:
awk '{ if (NR==14) {gsub($2, "/bla/bla/5/"); print} }' ill_5_06.hea
But it doesn't work if the second one is replace by a variable, too.
Maybe the problem could be solved if the content of $folder is not
Code:
folder=/bla/bla/

then
Code:
folder="/bla/bla/"

But how to tell awk that ' " ' isn't the beginning of a string? (folder=`pwd |awk '{print $1}'`). Because /" also doesn't work...

Thanks
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