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Find user owner of the most recently file in the system

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# 1  
Old 06-18-2010
Find user owner of the most recently file in the system
Good evening everybody,
I have to find the user owner of the most recently file in the system
How can I do? Smilie
# 2  
Old 06-18-2010
Use the search function, there are a lot of threads regarding this topic:

Google Search Results for most recent file | The UNIX and Linux Forums
This User Gave Thanks to Franklin52 For This Post:
Guccio
# 3  
Old 06-19-2010
I have solved in this way:

Code:
find / -type f | xargs ls -alrt | cut -f 2 | tail -n 1

The output is:

Code:
-rw------- 1 root  operator    7111  Jun 18 22:01 /root/.viminfo

How can I obtain from this output only the owner of this file?[COLOR="#738fbf"]

---------- Post updated at 02:49 AM ---------- Previous update was at 02:47 AM ----------

Solved SmilieSmilieSmilieSmilie

Code:
find / -type f | xargs ls -alt |  tail -n 1 | awk '{print $3}'

Last edited by Guccio; 06-19-2010 at 06:14 AM..
# 4  
Old 06-19-2010
Hi, that would work as long as there are no spaces in the filenames, otherwise you could use something like this if your find supports print0:
Code:
find / -type f -print0 | xargs -0 ls -alt | awk 'NR==1{print $3}'

(my ls -alt has the owner in the third column)

or this if it supports printf:
Code:
find / -type f -printf "%A@ %u\n" | sort -rn | awk 'NR==1{print $2}'

Last edited by Scrutinizer; 06-19-2010 at 07:17 AM..
# 5  
Old 06-19-2010
Ok but the problem is to find user owner most recently file in the system

If this user is "bin" ?

My solution find it!
# 6  
Old 06-19-2010
Code:
find / -type f -user bin -print0 | xargs -0 ls -art1 | tail -1

or
Code:
find / -type f -user bin -printf "%A@ %p\n" | sort -rn | awk 'NR==1{print $2}'

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