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# 1  
Old 06-11-2010
Find out whether files exist.
I have the following data stored in a file.
1 /home/file13 /home/file2
2 /home/file41 /home/file654
3 /home/file61 /home/file45
4 /home/file81 /home/file43
...


I want to print the first column provided the files represented by the second and third column exist.
How to do that?
# 2  
Old 06-11-2010
Hi, try with this:

Code:
while read linea
do
   fich1=$(echo $linea | cut -d" " -f2)
   fich2=$(echo $linea | cut -d" " -f3)

   if [ -e $fich1 ] && [ -r $fich1 ]
   then
      awk '{print $1}' $fich1
   fi
   if [ -e $fich2 ] && [ -r $fich2 ]
   then
      awk '{print $1}' $fich2
   fi

done < IN_FILE


SORRY!

I understood another thing....I have to improve my english.
Last edited by albertogarcia; 06-11-2010 at 04:14 AM.. Reason: I haven't understand the problem!
# 3  
Old 06-11-2010
Please try:

Code:
while read num f1 f2
do
   if [ -s "$f1" ] && [ -s "$f2" ]; then
      echo $num
   fi
done < file

-s will check for non zero size too. if you dont want to do that. just use -f
This User Gave Thanks to clx For This Post:
kevintse
# 4  
Old 06-11-2010
Thank you, anchal_khare.
The code works fine.
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