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egrep 4th line from match

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# 1  
Old 05-10-2010
Data egrep 4th line from match
Can some one help me to print 4th line before the match using egrep or grep command options.
i have a very large file and i need to search the entire file, look for the match (key word) and print 4th line before the matched key word.
# 2  
Old 05-10-2010
Code:
[house@leonov] cat test.file
four
three
two
one
gotcha
[house@leonov] grep -B4 'gotcha' test.file | head -n1
four

# 3  
Old 05-10-2010
Try...
Code:
awk '$0~s{print r[NR%b]}{r[NR%b]=$0}' b=4 s="keyword" file1

# 4  
Old 05-10-2010
Code:
while read line
do

echo $line | grep $pattern >/dev/null



if [ $? -eq 0 ]
then
echo $line4

fi

line4=$line3
line3=$line2
line2=$line1
line1=$line
done < $filename

This User Gave Thanks to amitranjansahu For This Post:
posix
# 5  
Old 05-10-2010
thanks to you all, i am looking single line command and i am getitng error for first two replies.

Code:
grep: illegal option -- B
grep: illegal option -- 4
Usage: grep -hblcnsviw pattern file . . .

-----------------------------------------------------

Code:
ksh: -ksh~s{print:  not found
awk: syntax error near line 1
awk: bailing out near line 1

------------------------------------------------------
Last edited by Scott; 05-10-2010 at 03:07 AM.. Reason: Code tags
# 6  
Old 05-10-2010
Make sure that you use the 'single quotes' around the awk code - as posted.
# 7  
Old 05-10-2010
hi,i tried with that option also. still getting error. below is my exact command.

# awk '$0~s{print r[NR%b]}{r[NR%b]=$0}' b=4 s="0x9f 0x81 0x19 0x01 0x02" test2.log | pg
awk: syntax error near line 1
awk: bailing out near line 1


there are some spaces in the key word am searching, will that matter?
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