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Problem with getting shell script to look two levels down...

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# 1  
Old 05-03-2010
Problem with getting shell script to look two levels down...
Hi,

I am writing a shell script and I need to make sure files exist two levels below a current directory so I use the following conditional check:

Code:
if [ '/var/spool/postfix/deferred/\*/\*' ]

The way the script seems to be working is that if something exists at the first level is executes the script. I only want it to execute if it is two levels below.

How can I go about doing this?
Last edited by mojoman; 05-03-2010 at 02:53 PM..
# 2  
Old 05-03-2010
I know you can use
Code:
if ls /var/spool/postfix/deferred/*/

Last edited by frans; 05-03-2010 at 04:22 PM..
# 3  
Old 05-03-2010
Quote:
Originally Posted by mojoman
I am writing a shell script and I need to make sure files exist two levels below a current directory so I use the following conditional check:

Code:
if [ '/var/spool/postfix/deferred/\*/\*' ]


That will always be successful because you are testing a non-empty string.
Quote:
The way the script seems to be working is that if something exists at the first level is executes the script. I only want it to execute if it is two levels below.

Code:
is_file()
{
  for f in "$@"
  do
    [ -f "$f" ] && return
  done
  return 1
}

if is_file /var/spool/postfix/deferred/*/*
then
   echo There are files 
else
   echo There are no files 
fi

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