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Problem in exiting a loop

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# 1  
Old 03-23-2010
Problem in exiting a loop
Hi my code looks like:

Code:
 
if test $STEP -le 10
then
.
.
 ls -1d AM*-OUT|while read MYDIR
 do
 cd $MYDIR
 ls |tail -n1| while read MYFILE
 do
 .
 .
 if test -s $MYFILE
 then
  sqlldr ....
  rc=$?
  
  if test $rc -ne 0
  then
    exit $rc
  fi
 fi 
 done 
 cd ..
done
fi

the exit highlighted exits from the current while loop and again the first while loop continues for next search of directory(highlighted in blue). I want to exit out of the beginning if loop ( exit out of both the while loops). please help. i tried with break instead of exit. tat is also not working.
Last edited by anijan; 03-23-2010 at 08:55 AM.. Reason: use code tags please,ty
# 2  
Old 03-23-2010
Hm what you describe should be the effect of break, not of exit. exit leaves the whole script, not just one loop. What shell are you using?
# 3  
Old 03-23-2010
I think it is working fine now... sorry.. it was a mistake from myside. Is there any way to retain the exit code ( or some value) for the next run of the script.?
# 4  
Old 03-23-2010
If you exit the script you will have to write it to a file so that it will be available for the next run.
If inside a a script you could move the stuff to do into functions and check the return code you get back from them with return <n>. Outside the functions you read it with $? and could decide by if/then/fi or whatever what to do.
This User Gave Thanks to zaxxon For This Post:
anijan
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