Controlled For Loop


 
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# 1  
Old 03-19-2010
Controlled For Loop

I have a for loop and i pass in number of times i want to loop as argument to script.


I have attached a snippet of my script. Problem is this does not work, if I manually replace the $NO_OF_LOOPS with a number in the script it works fine.

NO_OF_LOOPS=$1
for i in {0..$NO_OF_LOOPS}

Any help, i just want to control the no of loops via the argument i pass in.
# 2  
Old 03-19-2010
How about this!
Code:
NO_OF_LOOPS=$1
for i in `seq 0 $NO_OF_LOOPS`
do
        echo $i
done

# 3  
Old 03-19-2010
Code:
 
NO_OF_LOOPS=$1
for i in `seq  0 $NO_OF_LOOPS`

# 4  
Old 03-19-2010
Quote:
Originally Posted by murugaperumal
Code:
 
NO_OF_LOOPS=$1
for i in `seq  1 NO_OF_LOOPS`

This will not work.
Error:
seq: invalid floating point argument: _OF_LOOPS
Try `seq --help' for more information.

You need to precede $ infront of NO_OF_LOOPS

It should be like
Code:
for i in `seq  1 $NO_OF_LOOPS`

# 5  
Old 03-19-2010
Quote:
Originally Posted by thillai_selvan
This will not work.
Error:
seq: invalid floating point argument: _OF_LOOPS
Try `seq --help' for more information.

You need to precede $ infront of NO_OF_LOOPS

It should be like
Code:
for i in `seq  1 $NO_OF_LOOPS`


Now I corrected
# 6  
Old 03-19-2010
Or in bash

Code:
for ((  i = 1 ;  i <= $1;  i++  ))
do
	echo "amit $i"
done

# 7  
Old 03-19-2010
I get seq: command not found
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