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Shell Programming and Scripting

Extracting variables from echo

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# 8  
Old 03-08-2010
Code:
sed 's/^ *//g'

This is used to remove the leading white spaces
# 9  
Old 03-08-2010
try this,

Code:
date | awk ' { print $3,$2,$6,$4 } '

# 10  
Old 03-08-2010
Quote:
I say chomp because I remember the perl variant.


I guess chomp remove the trailing \n? !!
# 11  
Old 03-08-2010
Ya, of course. So do you want to remove the trailing white space characters?
# 12  
Old 03-08-2010
You can use the following code
Code:
declare -a array
declare -a array1
array1=(3,2,6,4);
count=1;
for i in `date| cut -d ' ' -f 1-8`
do
        array[$count]=$i;
        ((count++))
done

for j in `echo ${array1}|tr ',' ' '`
do
        echo ${array[${j}]} ;
done

# 13  
Old 03-08-2010
You mentioned that, chomp because I remember the perl variant. chomp used to remove the trailing newline only.
If you want to remove the trailing newline try this,

Code:
sed -r 's/\n$//'  

(or)
sed -re 's/(.*)\n$/\1/'
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