Shell Programming and Scripting

Will this work for you ?

Code:

awk 'BEGIN{FS=OFS=","}{for(i=1;++i<=NF;)$i=int($i)}1'

Does that work on your system? I suppose I might have a different version of awk. It appears to chop off everything up to the decimal place, at least on my system:

Code:

# echo 1200,135.000000,12.30100,3212.3200,1.759403,1230,101.101010,100.000000 | awk 'BEGIN{FS=OFS=","}{for(i=1;++i<=NF;)$i=int($i)}1'
1200,135,12,3212,1,1230,101,100

It appears that anbu23's solution works well. It makes sense, even, except that I don't understand a couple of minor things. Here's where my dampness behind the ears shows through, I'm afraid...

Code:

awk -F"," -v OFS="," ' { for(i=0;NF-i++;){ if($i ~ /[.]/){ sub("[.]*0+ *$","",$i) }}$1=$1}1'

I don't understand the purpose of the $1=$1 and the 1. They appear critical, but what do they do? Many thanks for the solutions offered. They serve well to show me where I can focus my learning.