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newbie: writing ksh shell problem

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# 1  
Old 02-17-2010
newbie: writing ksh shell problem
my default profile is using ksh, I tried to write a simple scripts and I had issues, below is my scripts:

Code:
$ more if_num.ksh
USAGE="usage: if_num.ksh"
print -n "Enter two numbers: "
read x y
if ((x=y))
then
  print "You entered the same number twice."


when I tried to executed the script below is the errors:

Code:
$ ./if_num.ksh
./if_num.ksh: line 3: print: command not found


thanks comments I did wrong here?

Thanks,
Last edited by pludi; 02-17-2010 at 04:54 PM.. Reason: code tags, please...
# 2  
Old 02-17-2010
Quote:
Originally Posted by matthew00
thanks comments I did wrong here?
You assumed a suffix would suffice to tell the OS what interpreter to run.

The correct way is to have this as first line:
Code:
#! /bin/ksh

You are certainly using a Unix variant that uses bash as default shell and bash doesn't implement "print".
# 3  
Old 02-22-2010
can someone please tell me what I did wrong here?
# 4  
Old 02-22-2010
You can write:
Code:
echo $SHELL

to know what shell are you using.
'print' is a ksh sentence but it is not in bash, so probably our shell is bash.
# 5  
Old 02-22-2010
thanks
# 6  
Old 02-22-2010
Matthew,
As suggested above, your first line of script should have interpretter that needs to be used to evaluate shell script. It can be
Quote:
#!/bin/ksh (or) #!/bin/bash
Can you let me know output of below command?

Quote:
echo $SHELL
# 7  
Old 02-22-2010
echo $SHELL tells you which shell you're currently working in, as an interactive shell. It has no relationship to the first line in a script.

---------- Post updated at 05:52 AM ---------- Previous update was at 05:48 AM ----------

Code:
if ((x=y))
then
  print "You entered the same number twice."

should be:

Code:
if ((x==y))
then
  print "You entered the same number twice."
fi

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