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find expression with awk in only one column, and if it fits, print whole column

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# 1  
Old 01-26-2010
find expression with awk in only one column, and if it fits, print whole column
Hi. How do I find an expression with awk in only one column, and if it fits, then print that whole column.
Code:
1 apple oranges
2 bannanas pears
3 cats dogs
4 hesaid shesaid

echo "which number:"
read NUMBER  (user inputs number 2 for this example)
awk " /$NUMBER/  {field to search is field one, the numbers} {print out bannanas pears}"

# 2  
Old 01-26-2010
Code:
$ cat input_file
1 apple oranges
2 bannanas pears
3 cats dogs
4 hesaid shesaid

$ read NUMBER

$ awk '$1 == N' N=$NUMBER input_file

Code:
sed -n "/^$NUMBER / s/[^ ] *//p"

Last edited by Scott; 01-26-2010 at 06:52 PM..
# 3  
Old 01-26-2010
Or:
Code:
sed -n "s/^$NUMBER *//p" infile

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