10 More Discussions You Might Find Interesting
1. UNIX for Beginners Questions & Answers
hi all
i am trying to tar and then zip files present dir by using the below command
tar -cvf ${abc}/xyz_backup_date_`date +%d%m%y%H%M%S`.tar xyz*
when the files are in less number the above command executes perfectly but when there are large number of files i am getting "arg list too... (5 Replies)
Discussion started by: manoj
5 Replies
2. Shell Programming and Scripting
I have a script on RedHat which runs this:
ssh -q -t -i $HOME/.ssh/my_key server2 "find ~/toCopy/*data* | xargs sudo mv -f -t /home/files/"
I'm getting:
sudo: unable to execute /bin/mv: Argument list too long
but the reason I use xargs is to avoid this restriction.
It used to work... (8 Replies)
Discussion started by: say170
8 Replies
3. Shell Programming and Scripting
Hi Team,
Here's the situation.
I have approximately 300000 to 500000 jpg files in /appl/abcd/work_dir
mv /appl/abcd/work_dir /appl/abcd/process_dir
The above move command will work if the jpg files count is close to 50000 (not sure). If the count is less this mv command holds good. But if... (14 Replies)
Discussion started by: kmanivan82
14 Replies
4. Shell Programming and Scripting
Hi I am using find command --
find "directory1" -type f | xargs -i mv {} "directory2"
to avoid above argument list too long problem.
But, issue i am facing is directory1 is having subdirectories due to this i am facing directory traversal problem as i dont want to traverse subdirectories... (9 Replies)
Discussion started by: VSom007
9 Replies
5. Shell Programming and Scripting
Dear Experts,
I have a list of 10K files in a directory. I am not able to execute any commands lile ls -lrt, awk, sed, mv, etc........
I wanna execute below command and get the output. How can I achieve it?? Pls help.
root# awk -F'|' '$1 == 1' file_20120710* | wc -l
/bin/awk: Argument list... (2 Replies)
Discussion started by: Naga06
2 Replies
6. Shell Programming and Scripting
I have a wrote a script which consits of the below line.. Below of this script I'm getting this error "ksh: /usr/bin/ls: arg list too long"
The line is
log_file_time=`ssh -i $HOME/.ssh/id_rsa -q $i ls -lrt /bp/karthik/test/data/log/$abc*|tail -1|awk '{print $8}'`
And $abc alias is as "p |... (1 Reply)
Discussion started by: 22karthikreddy
1 Replies
7. Shell Programming and Scripting
Hi everyone,
I have a problem with my shell script. As a quick overview I need to change a template file 6561 times and copy the file into a new catalogue. Thanks to your forum I have managed to write a script to do so:
#!/bin/sh
template=$1
for values in {45,165,285}\ {45,165,285}\... (6 Replies)
Discussion started by: mario8eren
6 Replies
8. UNIX for Dummies Questions & Answers
Hi
I executed the code
for file in `ls pdb*.ent`
do
new_name=`echo $file | sed 's/^pdb//;s/.ent/.txt/'`
mv $file $new_name
done
Its giving error at ' ls pdb*.ent' argument list too long
i have around 150000 entries
please help
Thank you (6 Replies)
Discussion started by: empyrean
6 Replies
9. UNIX for Dummies Questions & Answers
Hi,
I am trying to perform this task:
tar -cvf tar.newfile ??????.bas
I got error "arg list too long". Is ther any way around? I have about 1500 file need to be tar together.
Thanks in advance (5 Replies)
Discussion started by: jds3
5 Replies
10. Shell Programming and Scripting
Trying to tar specific files from a directory causes problems when the number of files is too large.
ls ~/logs | wc -l
5928
In the logs directory - I have 5928 files
If I want to include all files with today's date - I run the following command
tar cf ~/archive/LoadLogs_20060302.tar... (8 Replies)
Discussion started by: dad5119
8 Replies
