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Script to print first and last line have two pattern

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# 1  
Old 11-10-2009
Script to print first and last line have two pattern
Hello Guys,
I have file like
aaa
bbb
Line 1
cc
dd
Ser Nu 11223
ee
ff
Line 2
hh
hh
Ser Nu 44556
ii
jj

I need to match line starting with Line and Ser and only display them like

Line 1 Ser Nu 11223 | Line 2 Ser Nu 44556

The number of lines can be multiple Line 1 Line 2 Line 3 Line 4 ........Line 1000

---------- Post updated at 05:58 PM ---------- Previous update was at 04:44 PM ----------

sed -n '/Line/,/Ser/p'
this prints all the lines between the Line and Ser.
A small tweek is needed.........any takers.
# 2  
Old 11-10-2009
Code:
awk '/^Line/{s=$0;S++}/^Ser/{printf "%s%s %s",(S>1)?" | ":"",s,$0}' file



---------- Post updated at 05:59 PM ---------- Previous update was at 05:58 PM ----------

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# 3  
Old 11-10-2009
______________________________________________________________________________
awk '/^Line/{s=$0;S++}/^Ser/{printf "%s%s %s",(S>1)?" | ":"",s,$0}' aa
awk: syntax error near line 1
awk: illegal statement near line 1
_____________________________________________________

SunOS last-call-5 5.10 Generic_125100-10
______________________________________________________________________________

aa is the file name
# 4  
Old 11-10-2009
Try /usr/xpg4/bin/awk
# 5  
Old 11-10-2009
Thanks Danmero.
It worked.
If you have a moment to spare any explanation would be great Smilie
Sorry for being greedy Smilie
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