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awk,cut fields by change field format

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# 1  
Old 11-05-2009
awk,cut fields by change field format
Hi Everyone,

Code:
[root@]# cat 1.txt
1321631,77770132976455,19,20091001011859,20091001011907
1321631,77770132976455,19,20091001011859,20091001011907
1321631,77770132976455,19,20091001011859,20091001011907
[root@]# cat 1.txt | awk -F, '{OFS=",";print $1,$3,$4,$5}'
1321631,19,20091001011859,20091001011907
1321631,19,20091001011859,20091001011907
1321631,19,20091001011859,20091001011907
[root@]# cat 1.txt | cut -f1,3,4,5 -d ','
1321631,19,20091001011859,20091001011907
1321631,19,20091001011859,20091001011907
1321631,19,20091001011859,20091001011907
[root@]#

I can use either awk or cut to acheive the same result. If the finally output is:
1321631,19,20091001011859,20091001,011907
1321631,19,20091001011859,20091001,011907
1321631,19,20091001011859,20091001,011907
means to seperate the yyymmdd and hhmmss with ',', how should i do with awk or cut, or sed, etc, without open 1.txt, read the file, split','.

Thanks
# 2  
Old 11-05-2009
You can use the substr() function with awk:

Code:
awk -F, '{print $1,$3,$4,substr($5,1,8) FS substr($5,9)}' OFS="," file

# 3  
Old 11-05-2009
Thanks Frank, it works well.
How about if now
Code:
[root@]# cat 1.txt
1321631,7770125555555
1321631,888493949494933
1321631,07774560125666
1321631,4560125666
[root@]#

I have an array:
Code:
@prefix=qw(07774,888493,777);

The output should be like:
1321631,777,0125555555
1321631,888493,949494933
1321631,07774,560125666
1321631,,4560125666

So due to the 4th record no prefix in the predefined @prefix, so it is value is null.

I think:
Code:
awk -F, '{print $1,$2 ~ /@prefix/}' OFS="," 1.txt

i know above is wrong, please guide. Thanks
Thanks
Last edited by jimmy_y; 11-05-2009 at 08:13 AM..
# 4  
Old 11-05-2009
What kind of array is this? A Perl array?
# 5  
Old 11-05-2009
Quote:
Originally Posted by Franklin52
What kind of array is this? A Perl array?
Yes Frank, it is a perl array. Thanks
1.pl
Code:
#!/usr/bin/perl

my @prefix=qw(07774,888493,777);
my $cmd = "awk -F, '{print $1,$2 ~ /@prefix/}' OFS=',' 1.txt";
`cmd`;

# 6  
Old 11-05-2009
Unfortunately I'm not familiar with Perl. If you use Perl, awk should be redundant IMHO.

Hopely a Perl expert can give you the solution for your question...


Regards
# 7  
Old 11-05-2009
Quote:
Originally Posted by Franklin52
Unfortunately I'm not familiar with Perl. If you use Perl, awk should be redundant IMHO.

Hopely a Perl expert can give you the solution for your question...


Regards
Hi Frank, if without using perl, any solution for such scenario mo Smilie
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