Shell Programming and Scripting

hi. I need help my programing friends

I need to list all the files with a certain name (for example FileName) by last modification date but only the one with the last date. If there are two files with the same name and same modification date it should print the both.
For example in this set of files:

-rw-r--r-- 13 09/23/09 15:52:38 ./aa/FileName
-rw-r--r-- 16 09/23/09 15:52:38 ./cc/cc/FileName
-rw-r--r-- 16 09/23/09 15:54:34 ./cc/FileName
-rw-r--r-- 13 09/23/09 15:54:03 ./aa/dd/FileName
-rw-r--r-- 6 09/23/09 15:54:23 ./bb/FileName

it should return:

-rw-r--r-- 13 09/23/09 15:52:38 ./aa/FileName
-rw-r--r-- 16 09/23/09 15:52:38 ./cc/cc/FileName

because they have the same name and modification date.

I have this command but it list all files it finds:

ls -tl $(find . -name FileName)

Could someone help me?
Thanks in advance.

Pipe your command to:

Code:

<command> | awk 'NR==2{if(d==$3){print}exit}{d=$3}1'

Hi thanks for your response. But what it in this case:

-rw-r--r-- 13 09/23/09 15:52:38 ./aa/FileName
-rw-r--r-- 13 09/23/09 15:52:38 ./aa/dd/FileName
-rw-r--r-- 16 09/23/09 15:52:38 ./cc/cc/FileName
-rw-r--r-- 16 09/23/09 15:54:34 ./cc/FileName
-rw-r--r-- 13 09/23/09 15:54:03 ./aa/dd/FileName
-rw-r--r-- 6 09/23/09 15:54:23 ./bb/FileName

and I run your command it only shows me 2 lines when it is suppose to show 3 because the three first lines have the same modification date.

Code:

<command> | awk 'NR==1{d=$3FS$4}$3FS$4!=d{exit}1'

can you explain your command danmero ???

Code:

<command> | awk '
                           NR == 1       {d = $3 FS $4}   # On first line assign the value of $3 FS $4 to variable d
                           $3 FS $4 != d {exit}           # If value of $3 FS $4 not equal to value of variable d exit
                           1 '                            # 1 equal true, print each line

thanks,it's clear now...