Shell Programming and Scripting

hi all

i want to delete a line upto a particular character. here is example.

cp cms/images/wifi-zone.png

i want to delete the line till . (cp cms/images/wifi-zone.) so the output wud be "png" only

how can i do it?

also please note down that dot (.) can also occur multiple times. so i need that delete the whole line till the occurrence of last dot (.) in the line.

e.g

input wud be...

cp cms/images/wifi-zone.css.php

and output wud be

php

Thanks in advance.

kashif

Code:

# with shell:
$> A='cp cms/images/wifi-zone.css.php'
$> echo ${A##*.}
php
with sed:
$> echo 'cp cms/images/wifi-zone.css.php'| sed 's/.*\.\([^.]*\)$/\1/'
php

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Code:

$sed 's/.*\.//g'
cp cms/images/wifi-zone.css.php
php

Entered input in Stdin in the above execution.

Thank You very much guys. both solutions are working fine. this is really awesome. Hats Off for you people.

Code:

 echo 'cp cms/images/wifi-zone.css.php'| sed 's/.*\.//'

Code:

 echo 'cp cms/images/wifi-zone.css.php'| awk -F. '{print $NF}'

Code:

echo 'cp cms/images/wifi-zone.css.php'| grep -o '[^.]*$'

Thank You all. now i got the totally opposite scenario.

i need that keep the line till the occurrence of last slash (/) and delete anything after that.

e.g

input wud be...

cp cms/images/wifi-zone.css.php

and output wud be

cp cms/images/

Thanks in advance.

Solution 1

Code:

$ dirname "cp cms/images/wifi-zone.css.php"
cp cms/images

Solution 2

Code:

$ sed 's/\/[^\/]\+$//'
cp cms/images/wifi-zone.css.php
cp cms/images