How to grep for certain pattern


 
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# 1  
Old 09-15-2009
How to grep for certain pattern

Hi
I have a file in the following format:

------------------------------------------------------------
227/228 105/106 237/238 087/088 329/330 331/332 340/341
------------------------------------------------------------
#1 272 * * * * * * 2103 233
#2 * * * 2052 * * * 932 2478
#3 * * * 2315 * * * * 2342
------------------------------------------------------------
115/116 344/345 335/336 337/338 071/072 333/334 266/267
------------------------------------------------------------
#24 * 2238 * 2368 * 2138 * 2110
#26 2383 * 2205 * * * * * 2710

etc.....

I need to "grep" the first instance of the line located between "--------"
so the output would be the following:

227/228 105/106 237/238 087/088 329/330 331/332 340/341

Is there a way to to this? Thanks for any help -A
# 2  
Old 09-15-2009
if the file is same always,

Code:
grep -v -- "--------" file | head -1

# 3  
Old 09-15-2009
Thanks
# 4  
Old 09-15-2009
this also do
Code:
awk '/-----/{next}{print}{exit}'  filename

# 5  
Old 09-15-2009
or..
Code:
sed -n '/---/,/---/ p' file

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