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Script to find folders with spaces and end of files and directories

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# 1  
Old 07-15-2009
Script to find folders with spaces and end of files and directories
Hi
I need a script that can search through a set of directories and can locate any file or directory that has a space at the end
Filename(space)
Foldername(space)
I then need to remove that space within the script
Hope someone can help
thanks in advance
Treds
# 2  
Old 07-15-2009
Using some posix-sh, ksh, bash, ...:
Code:
for f in *" "
do
 echo "<$f>"
 new=${f/% /}
 # no overwrite, if there is   xxx<space> and xxx
 if [ ! -e "$new" -a "$new" != "$f" ] ;
 then
        mv "$f"  "$new"
 else
        echo "can't do it"
 fi
done

# 3  
Old 07-15-2009
hi
i could not get that to work. (please excuse bit of a novice)
I copied and pasted what you posted into a script.
I generated a folder
inside the folder i created 2 files and 2 folders one with space and one without
i ran script from inside that directory and got a error. i have pasted the steps i did along with the script. Also if this script work would in drill done to multiple folder depths as this is my made problem

Code:
drwxrwxrwx   4 root root   8192 Jul 15 17:58 .
drwxrwxrwx  17 lp   lp     8192 Jul 15 17:42 ..
-rwxrw-rw-   1 root root 886004 Jun 18 18:26 Picture 1ï¨
-rwxrw-rw-   1 root root 886004 Jun 18 18:26 Picture 2
drwxrwxrwx   2 root root   8192 Jul 15 17:42 test1ï¨
drwxrwxrwx   2 root root   8192 Jul 15 17:42 test2
-rwxrwxrwx   1 root root    217 Jul 15 17:58 test.sh
[root@TAG-468 TEST]# ./test.sh
<* >
mv: cannot stat `* ': No such file or directory
[root@TAG-468 TEST]# more test.sh
#!/bin/sh

for f in *" "
do
 echo "<$f>"
 new=${f/% /}
 # no overwrite, if there is   xxx<space> and xxx
 if [ ! -e "$new" -a "$new" != "$f" ] ;
 then
        mv "$f"  "$new"
 else
        echo "can't do it"
 fi
done


thanks
Treds
Last edited by Yogesh Sawant; 07-17-2009 at 07:30 AM.. Reason: added code tags
# 4  
Old 07-15-2009
Please post the output from:

Code:
ls -la | sed -n l

And:

Code:
ls -lab

Based on "kshji" script execution results I don't believe that the trailing character is a space character.
# 5  
Old 07-16-2009
hi output
Code:
[root@TAG-468 TEST]# ls -la | sed -n l
total 3568$
drwxrwxrwx   4 root root   8192 Jul 15 17:58 .$
drwxrwxrwx  17 lp   lp     8192 Jul 15 17:42 ..$
-rwxrw-rw-   1 root root 886004 Jun 18 18:26 Picture 1\357\200\250$
-rwxrw-rw-   1 root root 886004 Jun 18 18:26 Picture 2$
drwxrwxrwx   2 root root   8192 Jul 15 17:42 test1\357\200\250$
drwxrwxrwx   2 root root   8192 Jul 15 17:42 test2$
-rwxrwxrwx   1 root root    217 Jul 15 17:58 test.sh$
You have new mail in /var/spool/mail/root
[root@TAG-468 TEST]# ls -lab
total 3568
drwxrwxrwx   4 root root   8192 Jul 15 17:58 .
drwxrwxrwx  17 lp   lp     8192 Jul 15 17:42 ..
-rwxrw-rw-   1 root root 886004 Jun 18 18:26 Picture\ 1ï¨
-rwxrw-rw-   1 root root 886004 Jun 18 18:26 Picture\ 2
drwxrwxrwx   2 root root   8192 Jul 15 17:42 test1ï¨
drwxrwxrwx   2 root root   8192 Jul 15 17:42 test2
-rwxrwxrwx   1 root root    217 Jul 15 17:58 test.sh
[root@TAG-468 TEST]#

thanks
treds
Last edited by Yogesh Sawant; 07-17-2009 at 07:29 AM.. Reason: added code tags
# 6  
Old 07-16-2009
These are not trailing spaces:

Quote:
Picture 1\357\200\250$
test1\357\200\250$
The \nnn format gives you the actual character in octal. These three characters are all outside the normal printable range and may look like spaces in a "ls" display.

There are three trailing characters at the end of each of these names:
\357
\200
\250

It is possible to generate these characters in shell and use them in commands:

e.g.

Code:
SUFFIX=echo "\0357\0200\0250\c"

ls -la *"${SUFFIX}"

# 7  
Old 07-20-2009
thanks but think thats a bit over my head
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