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Grepping text by providing line numbers.

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# 1  
Old 06-22-2009
Grepping text by providing line numbers.
Dear Friends,
I have a flat file from which I want to grep line no. 7,10, 19 to 35, 37.
How can it be done?

Thank you in advance
Anushree
# 2  
Old 06-22-2009
Hi.

When you say "grep lines", do you mean extract lines?

There are a number of tools that can do this.

But based on what you asked, this should work...

sed "7p;10p;19,35p;37p;d" my_file | grep "....."
# 3  
Old 06-22-2009
Code:
awk 'NR ~ /^(7|10|19)$/' file

# 4  
Old 06-22-2009
Use gawk, nawk or /usr/xpg4/bin/awk on Solaris:

Code:
awk 'NR~/^7|1[09]|2[0-9]|3[0-5,7]$/' infile

Last edited by radoulov; 06-22-2009 at 12:04 PM..
# 5  
Old 06-22-2009
One way to do it in perl:

Code:
perl -ne 'BEGIN{foreach $i (7,10,(19..35),37){$x{$i}=1}}{print if $x{$.}==1}' infile

tyler_durden
# 6  
Old 06-22-2009
Quote:
Originally Posted by durden_tyler
One way to do it in perl:
[...]
Code:
(19..35)...

I have to read more carefully,
I corrected my post.

Using the same logic with Perl:

Code:
perl -ne'$.=~/^7|1[09]|2[0-9]|3[0-5,7]$/and print' infile

Last edited by radoulov; 06-22-2009 at 12:09 PM..
# 7  
Old 07-01-2009
Hey friends
Almost all solutions worked fine
Thank you for the quick reply.
Take care.
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