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String compare with list in shell script

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# 1  
Old 06-11-2009
Network String compare with list in shell script
Hi ,

I am new to shell scripting.

below is my requirement :
1) while running my .sh i will pass a string
2) i have to extract a folder name under a /config folder
3) i need to compare a input string in the folder name list
4) if that is true i have to continue my job else i have to give the message to the user

here is my code :

Code:
if [ $# -ne 1 ]; then
echo "Invalid arguments!"
echo ""
echo "job Name: $(basename $0) "
echo " Please pass the environment variable "
return 1
else
env_name="$1"
fi
 
LIST="`ls -ltr conf/ | grep -v "total" | grep -v "pre_swh" | awk '{ print $NF "," }'`";
if ["$env_name" in "$LIST"]
then
echo "correct"
else
echo "incorrect"
fi
counter1=`expr $counter1 + 1`
#done

while running this am gettin the error
sample2.sh[25]: [test: not found. Smilie

Please anyone help me on this
Last edited by vidyadhar85; 06-11-2009 at 10:47 PM.. Reason: code tag added
# 2  
Old 06-11-2009
if loop syntax is wrong
Code:
if [ "$env_name" = "$LIST" ] ; then

# 3  
Old 06-11-2009
Thank you vidyadhar.

but still am getting the same error..

is any other way there for getting the folder name and compare that with the input string?

Regards,
Raji.
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