Shell Programming and Scripting

Hi,

i have say 100 files in a directory.

file1.log
file2.log
file3.log
file4.log
file5.log
file6.log
...
...
...
file99.log
file100.log
=========
I need to create another file which contains the list of al these log files.
each file should contain only 10 log file names.
it shud be like

filename1.list --- can contain first 10 log file, may be based on the timestamp.

filename2.list --- next 10 files.

So since we have 100 log files in this location, we need to get 10 filename*.list with 10 files in each file..


Did i confuse with the question? please let know

Please help

Regards,
Robz

Hello,

Here is a logic that you can use. Try to implement it and ask if you have problems constructing the statements.

1. List al the log filenames.
2. add the names to an array.
3. loop through the array writing 10 records to a file
4. change filename when 10 records are written

Regards,
HKansal

thanks bro.. but am writing a Shell script for this..

Array seems not possible...

u got any code snippet

Regards,
Robin Paulose

somewhat like this can work...modify it if u need...

Code:

set -A _Array `ls file*`
i=0
j=10
for file_name in ${_Array[@]}
do
   if [[ $j -eq 10 ]]; then
      j=0;
      (( i = $i + 1 ))
      >filename$i.list
   fi
   echo $file_name >> filename$i.list
   (( j = $j + 1 ))
done

Here I would say "good job Rakesh" as you captured the logic I stated earlier.

But I would have considered it better to give that step wise. Anyways, the job's done I guess.

Regards,
HKansal