Need to cut filename in LINUX ksh


 
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# 1  
Old 06-08-2009
Need to cut filename in LINUX ksh

Hi,
I need to cut filename in Linux ksh.
for example file name is c_xxxx_cp_200908175035.zip. I need to get variable with only c_xxxx_cp value.
# 2  
Old 06-08-2009
what have you tried?
# 3  
Old 06-08-2009
dir_name=${zip_file%.*}
dir_name_1=${dir_name#*JULIY/}

This will give me file name without ".zip", but still I have to get rid of timestamp.
# 4  
Old 06-08-2009
the last "_" underscore is before the extension. therefore you can use % which means "shortest match from the back"
Code:
${zip_file%_*}

please read again Advance Bash guide (google) for details on string manipulation
# 5  
Old 06-08-2009
Thanks a lot.
# 6  
Old 06-09-2009
Even Simpler :

echo "c_xxxx_cp_200908175035.zip" | cut -d "." -f 1 | cut -d "_" -f 1,2,3
# 7  
Old 06-09-2009
Quote:
Originally Posted by dcoolsam
Even Simpler :

echo "c_xxxx_cp_200908175035.zip" | cut -d "." -f 1 | cut -d "_" -f 1,2,3
certainly not simpler. you don't need to call 2 cuts.
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