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Check in awk about a value of variable

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# 1  
Old 03-30-2009
Check in awk about a value of variable
I need to check if a variable have numeric value and if yes how many digits does it have, how do i do it?
# 2  
Old 03-30-2009
Code:
#
# return number of digits if str is all digits
# otherwise return 0
#
function countdigits( str )
{
   digits = 0
   len = split( str, a ,"" )
   for ( i = 1; i <= len; i++ )
       if (( a[i] + 0 ) == a[i] )
          digits++

   if ( len == digits )
      return digits
   else
      return 0
}

# 3  
Old 03-30-2009
Quote:
Originally Posted by tal
I need to check if a variable have numeric value and if yes how many digits does it have, how do i do it?
Something like this?

Code:
awk 'int(var) == var {print length(var)}'

Regards
# 4  
Old 03-30-2009
Hammer & Screwdriver Another approach
I added the "nope" to make it easier to see the output.

Code:
> echo 159a | awk '{ink2=ink=$0;lenx=length(ink); gsub("[:alpha:]","",ink2); leny=length(ink2); if (lenx==leny){print lenx}else{print "nope"}}'
nope
> echo 159a1 | awk '{ink2=ink=$0;lenx=length(ink); gsub("[:alpha:]","",ink2); leny=length(ink2); if (lenx==leny){print lenx}else{print "nope"}}'
nope
> echo 1591 | awk '{ink2=ink=$0;lenx=length(ink); gsub("[:alpha:]","",ink2); leny=length(ink2); if (lenx==leny){print lenx}else{print "nope"}}'
4
> echo a1591 | awk '{ink2=ink=$0;lenx=length(ink); gsub("[:alpha:]","",ink2); leny=length(ink2); if (lenx==leny){print lenx}else{print "nope"}}'
nope

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