Shell Programming and Scripting

Hi,

please tell me how to convert hex number to decimal

000000E7
000000000002640D
0000000000025B16

and seconds to minutes, hours, days, months, years
bytes to kbytes, mbytes , gbytes

read the following examples
while read a b
do
printf "%5d %5d\n" "0x$a" "0x$b"
done < "$FILE"
#!/bin/ksh
# this does the math
echo "c1:41 c2:0x0000.00046b3e" | awk -F[:\.] '{ print $3, $4}' | read one two
result=$( printf "%d + %d" $one 0x"$two")
echo $result
result=$( printf "%d + %d" 0x0x000 0x00046b3e ) # check
echo $result
printf "%d\n" "0x00046b3"
but I would like to learn syntax either
as in my case, the last line generated -1

thanks

Jack

To convert hex to decimal try using bc
Eg:- bc
ibase=16
3039
12345

and the second part of conversion of seconds to min 1 min = 60 sec so if $x sec is given $x/60 will give u min and so on

similarly for bytes use 1000 or 1024 as a standard

Thanks for your excellent solution.
Unfortunately neither my Linux embedded machine not Nokia Tablet come
with bc installable package.
So I have to look for another shell based only solution.

Great idea is to use in bc - input and out base (there is a number of good bc calculator examples I learned from Google).

For seconds conversion it would be nice to use timestamp, datetime
to read seconds as input and output result in one of available formats,
the same with bytes to Mbytes, Gbytes conversion,
as I need to write another conversion script for use in main script.

minutes = seconds (mod 60)

expr 5 % 3
2
works fine for constants

didn't work for seconds as variable
/="slash-equal" (divide variable by a constant)
%="mod-equal" (remainder of dividing variable by a constant)
It started to work for me as in the following example
# If you need a random int within a certain range, use the 'modulo' operator.
# This returns the remainder of a division operation.

RANGE=500

echo

number=$RANDOM
let "number %= $RANGE"
# ^^
echo "Random number less than $RANGE --- $number"
-
for remainder
seconds %= seconds
for minutes
minutes /= seconds
..

a=9
let "a %= 4"
echo $a
1

so a mod(4) = 1, exactly as 9 = 2*4 + 1 -

for conversion of seconds I would like to use epoch time
and date +%s
I get 95958

should be

The current Unix epoch time is 1236954365


-
-
What is epoch time?

The Unix epoch (or Unix time or POSIX time or Unix timestamp) is the number of seconds that have elapsed since January 1, 1970 (midnight UTC/GMT), not counting leap seconds. The epoch timestamp 0 can be written in ISO 8601 format as: 1970-01-01T00:00:00Z. One epoch hour is 3600 seconds, one epoch day is 86400 seconds long, leap seconds are not calculated. Many Unix systems store epoch dates as a signed 32-bit integer, which might cause problems on January 19, 2038 (known as the Year 2038 problem or Y2038).

Human readable time Seconds 1 minute60 seconds 1 hour3600 seconds 1 day86400 seconds 1 week604800 seconds 1 month (30.44 days) 2629743 seconds 1 year (365.24 days) 31556926 seconds

Jack

Please use [ code ][ /code ] (sans the space) for code/logs/listings/...

Code:

$ TIME=$( date +%s )
$ LANG=C date -ud @`echo $TIME`
Fri Mar 13 14:37:15 UTC 2009
$ SEC=$(( ${TIME} % 60 ))
$ MIN=$(( ${TIME} % 3600 / 60 ))
$ HR=$(( ${TIME} % (3600*24) / 3600 ))
$ echo $HR $MIN $SEC
14 37 15
$
$
$ SIZE=$(( 200*1024*1024 ))
$ KB=$(( ${SIZE} / 1024 ))
$ MB=$(( ${SIZE} / 1024 / 1024 ))
$ GB=$(( ${SIZE} / 1024 / 1024 / 1024 ))
$ BITS=$(( ${SIZE} * 8 ))
$ echo $GB $MB $KB $SIZE $BITS
0 200 204800 209715200 1677721600
$

This code worked both on Linux/HP-UX using bash/ksh on both (except for the second date call, HP-UX' date doesn't like the -d switch). As for the Base-16 to Base-10 conversion, it's probably easier to do that in Perl than to code in in the shell.

Hi,

in my case
running
$ time=$( date +%s )
$ lang=c dat -ud @`echo $time`
generated
date: invalid date `@103798`

Jack

what's "%s" - it's valid options under Solaris? What OS are you under? What's it supposed to return?
what's 'dat'?
Why are you doing this: '@`echo $time`'? What '@' for? Why do you need 'echo'?

What are you trying to achieve?

Hi,

just tested code from reply in this thread.
-
-

$ TIME=$( date +%s )
$ LANG=C date -ud @`echo $TIME`
Fri Mar 13 14:37:15 UTC 2009

-
Jack